hi, could smne pls give me an idea of how to deal with this problem? Suppose that f(0) = 0 and that f'(0) =1 , calculate f(f(f(x))) at point x=0 thanks a lot, any hint at all would b helpful, as i completely clueless.
if f(0) = 0 then f(f(0)) = f(0) = 0.. it's recursive. I am not sure why you would need f'(x) to solve nothing to do with derivatives. Are you sure you typed the question correctly?
here it is again: f(0) = 0 and f'(0) = 1 calculate the derivative of f(f(f(x))) at point x=0 that's the exact question. thanks for the help on the second question
Oh I see calculate the DERIVATIVE of f(f(f(0))) First lets set g(x) = f(f(x)) g'(x) is therefore f'(f(x))*f'(x) Derivative f(g(x)) after substitution is f'(g(x))*g'(x) = f'(f(f(0)))*f'(f(0))*f'(0) What a mouthful. If I were to venture a wild crazy guess I'd say that simplifies to 1.
oh great! i just worked it out, it did come to 1. thanks a lot. can u give a further hint on the other question, i'm still a bit confused there. thanks again, marvellous!