# Redox equations balancing

1. Sep 26, 2005

### dajugganaut

hi all, my chemistry assignment had a bunch of questions on redox equations balancing. i got stuck on this one:

$$\CrI_{3} + KOH + \Cl_{2} \rightarrow \K_{2}CrO_{4} + \KIO_{4} + KCl + \H_{2}O [\tex] so far, i tried to find ON numbers of the various elements. Cr changes from +3 to +6 I changes from -1 to +7 Cl changes from 0 to +1 this means that Cr and I undergo a loss of electrons, while Cl undergoes a gain. i dont know how to solve this question when there are multiple LEO. can you help? =) [ EDIT : my attempt at LATEX has proved to be yet another disaster ] Last edited: Sep 26, 2005 2. Sep 26, 2005 ### stunner5000pt For your latex in the final tex it should be a FORWARD SLASH, not a backslash... thus the mess. Also you don't need a backslash to start off a new word. ANyway it look like this: [tex] CrI_{3} + KOH + Cl_{2} \rightarrow K_{2}CrO_{4} + KIO_{4} + KCl + H_{2}O$$

i suggest you break into half cells as follows
$$CrI_{3} \rightarrow K_{2}CrO_{4} + KIO_{4}$$
$$KOH \rightarrow H_{2}O$$
$$Cl_{2} \rightarrow KCL$$

Balance everything exotic (like K, Cr, I, Cl) first. Then follow the usual steps for half cells. I know it doesn't look like it will work.. but if you balance each half cell properly in temrs of charge and atoms yu should be fine