1) Give the resultant fomula for: Cr2+ gets reduced.
2) Will the following reaction occur? Acidified K2Cr2O7 solution is added to HNO3(nitric acid).
The Attempt at a Solution
1) I put: Cr+2 + 2e- ---> Cr(s); I have one question though...doesn't this half-reaction not exist?
2) I put no for this question because I saw that all 4 species are oxidizers. But I am just wondering, if it says acidified K2Cr2O7, does that just refer to: the reaction with Cr2O7-2 that includes 14H+?