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Redox with 3 half reactions

  1. Apr 8, 2004 #1
    KBrO2 + KI + HBr ---> KBr + I2 + H2O

    eq1
    KBrO2 ---> KBr
    4e- + 4H+ +KBrO2 ---> KBr + 2H2O

    eq2
    2KI ---> I2 + 2K+ + 2e-
    4KI ---> 2I2 + 4K+ + 4e-

    eq3
    HBr ---> KBr
    K+ + HBr ---> KBr + H+

    since the charges in eq3 are +1=+1
    you don't have to multiply this equation by 4 do you?

    3H+ + KBrO2 + 4KI + HBr ---> 2KBr + 2H2O + 2I2 + 3K+


    Haven't been able to find any examples or problems with
    redox using 3 half reactions in any of my text books. Why
    wouldn't they put a few in there?
     
    Last edited: Apr 9, 2004
  2. jcsd
  3. Apr 9, 2004 #2
    eq3
    HBr ---> KBr
    K+ + HBr ---> KBr + H+

    multiply eq3 by 4 so K+ will cancel

    4K+ + 4HBr ---> 4KBr + 4H+

    adding all three:

    KBrO2 + 4KI + 4HBr ---> 5KBr + 2H2O + 2I2
     
    Last edited: Apr 15, 2004
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