[SOLVED] Reduce Order (diff eq) nevermind i got it, cliffsnotes ftw 1. The problem statement, all variables and given/known data Solve the differential equation using the reduction of order method. [tex]t^2 y'' - 4ty' + 6y = 0[/tex] [tex]t > 0[/tex] [tex]y_1 (t) = t^2[/tex] 2. Relevant equations 3. The attempt at a solution Well The first thing I do is [tex]y(t) = v(t) t^2[/tex] Then I find y' and y'' and plug into the original diff eq and get [tex]t^4 v'' = 0[/tex] Which I'll assume is correct. But now I'm really not sure what to do with that. I could do integration by parts? but that doesn't seem to lead anywhere. How do I get from there to t^3 (the other solution)?