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nevermind i got it, cliffsnotes ftw

1. The problem statement, all variables and given/known data

Solve the differential equation using the reduction of order method.

[tex]t^2 y'' - 4ty' + 6y = 0[/tex]

[tex]t > 0[/tex]

[tex]y_1 (t) = t^2[/tex]

2. Relevant equations

3. The attempt at a solution

Well The first thing I do is

[tex]y(t) = v(t) t^2[/tex]

Then I find y' and y'' and plug into the original diff eq and get

[tex]t^4 v'' = 0[/tex]

Which I'll assume is correct.

But now I'm really not sure what to do with that. I could do integration by parts? but that doesn't seem to lead anywhere. How do I get from there to t^3 (the other solution)?

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# Homework Help: Reduce Order (diff eq)

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