Solve : y''+(2/x)y'+y=0 given that y=sinx/x is a solution
The Attempt at a Solution
y=vsinx/x is the other solution
I worked out
to work out y'' got extremely confusing for me,so I used an online differentiator to do it.
It gave y'' as
Now when I substitute it back into the equation, I keep getting the terms for v to not cancel and I get one complex differential equation.