Reduction of Order

  1. 1. The problem statement, all variables and given/known data

    solve y"-4y'+4y=0 y1=e^(2x) using reduction of order

    3. The attempt at a solution

    I then substitute that into the original equation to get


    simplify to get

    from here I do not know what to do...I do know the answer is suppose to be xe^2x, but I don't know how that is done.
  2. jcsd
  3. rock.freak667

    rock.freak667 6,231
    Homework Helper

    From u"e2x=0, you can divide by e2x and solve u''=0.
  4. then u"=0 makes u'=c and then later u=xc1+c2 and

    but what then? how do I solve for c1 and c2?
  5. Mark44

    Staff: Mentor

    You need initial conditions in order to solve for the constants c1 and c2.
  6. however, in my solutions manual it says the solution comes out to be xe^2x, and I have no idea how that came to be. except for the use of this equation
    y2=y1S e^(-SP(x)dx)/y1^2 dx
  7. Mark44

    Staff: Mentor

    The general solution of your diff. equation is y = c1e^(2x) + c2xe^(2), for any values of c1 and c2. The simplest pair of linearly independent solutions is the pair with c1 = c2 = 1, so maybe they just arbitrarily chose that one.
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