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Reduction of PbCl2

  1. Mar 16, 2017 #1
    1. The problem statement, all variables and given/known data
    A question asked to write an equation for the reduction of PbCl2

    The answer key was
    PbCl2+X ----> Pb+XCl2
    where X can be: .....Fe, Mg.....but not Na or K

    Why are Na or K not acceptable?
  2. jcsd
  3. Mar 16, 2017 #2
    Cost could be one reason. And which would you rather work with: sodium / potassium vs. iron / magnesium?
  4. Mar 16, 2017 #3


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    Based on the activity series, all of those metals should be able to displace Pb2+ in a single displacement reaction. Maybe it just has to do with the fact that FeCl2 and MgCl2 are valid formula but NaCl2 and KCl2 are not (rather the equation would be PbCl2 + 2Na --> Pb + 2NaCl).
  5. Mar 17, 2017 #4
    The question doesnt make any such type of recommendation though
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