For the circuit attached, I'm first asked to find [tex] I_1, I_2, V_1, V_2 [/tex] by using the appropriate loop equations. I got these answers (which I checked and are correct):(adsbygoogle = window.adsbygoogle || []).push({});

[tex] \overline{I_1} = 1.556A\angle61.4^\circ [/tex]

[tex] \overline{I_2} = 1.111A\angle-100.25^\circ [/tex]

[tex] \overline{V_1} = 3.92V\angle139.8^\circ [/tex]

[tex] \overline{V_2} = 1.57V\angle-55.25^\circ [/tex]

My questions are these:

1. I got the value of V_{2}by multiplying I_{2}with (1 - j2 + j3). Why on earth don't I get the same answer if I use the fact that [tex] V_2 = I_{2}j2 + I_{1}X_{m} [/tex]

Where X_{m}is the impedance as a result of the mutual inductance which I calculated using [tex] X_m = k\sqrt{j4 * j2} [/tex].

Also, shouldn't V_{2}be a stepped up/down version of V_{1}but phase shifted by 180 degrees? (from the dot convention)

2. How can I obtain the same results using the reflected impedance concept? Without knowing the turns ratio I can't do this and I can't seem to be able to find a way to find the turns ratio by using the coupling coefficient 'k' or any other of the known data. A hint would be much appreciated.

Thank you in advance for any help you can offer!

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# Homework Help: Reflect Impedance

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