# Reflecting image in a lens

• fball558
In summary, the problem involves finding the distance between an object and the final image formed by two lenses, one with a focal length of 0.62 m and the other with a focal length of -2.7 m. Using the equations (1/x1)+(1/image)= (1/0.62) and (1/x2 - image) + (1/x3)= (1/-2.7), the attempts at a solution involve solving for the image distance in the first equation and x3 in the second equation, resulting in a final image distance of 0.526 m. However, the solution may be incorrect and further assistance is needed.
fball558

## Homework Statement

An object is 1.75 m to the left of a lens of focal length 0.62 m. A second lens of focal length -2.7 m is 0.52 m to the right of the first lens. Find the distance between the object and the final image formed by the second lens.

## Homework Equations

(1/x1)+(1/image)= (1/focal point 1)

(1/x2 - image) + (1/x3)= (1/focal point 2)

## The Attempt at a Solution

i use
x1=1.85
focal 1 = .62
solve for image in first equation

then use

x2=.52
focal 2 = -2.7
use the second equation and solve for x3
and get .526 m
i think I am following the steps right, but keep getting the wrong answer. any help would be great
thanks!

In the problem xq1 is 1.75.
What is image distance?

Your approach to solving this problem is correct. However, it is important to note that when dealing with lenses, the sign convention for focal length is different. A positive focal length indicates a convex lens, while a negative focal length indicates a concave lens. In this problem, the second lens has a focal length of -2.7 m, indicating that it is a concave lens. This means that the image formed by this lens will be virtual and located on the same side as the object. Therefore, the distance between the object and the final image will be the sum of the distances between the object and the first lens, and between the first lens and the second lens. In this case, the distance will be (1.85 + 0.52) m = 2.37 m. This is because the virtual image formed by the second lens will appear to be 0.52 m to the right of the first lens, which is already 1.85 m to the left of the object. I hope this helps clarify the solution for you.

## 1. How does a lens reflect an image?

A lens reflects an image through a process called refraction. When light enters the lens, it is bent and focused onto a specific point, creating an inverted and magnified image on the other side of the lens.

## 2. What type of lens is best for reflecting images?

A concave lens is best for reflecting images, as it causes light rays to diverge and creates a virtual image. This type of lens is commonly used in telescopes and microscopes.

## 3. Can a lens reflect an image without light?

No, a lens needs light in order to reflect an image. Without light, there would be no rays to bend and focus onto a point, resulting in no image.

## 4. How does the shape of a lens affect the reflecting image?

The shape of a lens determines its focal length, which affects how light is bent and focused. A convex lens has a shorter focal length, resulting in a magnified image, while a concave lens has a longer focal length, resulting in a smaller image.

## 5. Are there any real-life applications of reflecting images in lenses?

Yes, there are many real-life applications of reflecting images in lenses. Some examples include cameras, telescopes, microscopes, and eyeglasses. Reflection in lenses is also used in the medical field for procedures such as laser eye surgery.

• Introductory Physics Homework Help
Replies
3
Views
456
• Introductory Physics Homework Help
Replies
10
Views
1K
• Introductory Physics Homework Help
Replies
1
Views
1K
• Introductory Physics Homework Help
Replies
1
Views
1K
• Introductory Physics Homework Help
Replies
2
Views
828
• Introductory Physics Homework Help
Replies
5
Views
1K
• Introductory Physics Homework Help
Replies
7
Views
2K
• Introductory Physics Homework Help
Replies
7
Views
1K
• Introductory Physics Homework Help
Replies
2
Views
1K
• Introductory Physics Homework Help
Replies
3
Views
914