Reflection grating

  1. 1. The problem statement, all variables and given/known data
    [​IMG]


    2. Relevant equations
    d=1/N d*sin(theta)=m*(lambda)


    3. The attempt at a solution
    d=1/1970
    d=.0005076

    .0005076*sin(theta)=2*600e-9

    sin(theta)=.0000012/.0005076

    arcsin(.002364)=.135º

    *sigh*
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. hage567

    hage567 1,538
    Homework Helper

    One thing I see is that when you found d you didn't convert from cm to m, so you have inconsistent units in your equation.
     
  4. d=.0005076cm = .000005076m

    .000005076*sin(theta)=2*600e-9

    sin(theta)=.0000012/.000005076

    arcsin(.2364)=13.7º

    Anything else I'm missing, because the answer is not 13.7º?
     
  5. hage567

    hage567 1,538
    Homework Helper

    Why do you have m=2? If it is first order I would think it would be m=1.
     
  6. hage567

    hage567 1,538
    Homework Helper

    Are you sure you are using the right equation? I think the grating equation you are using is not quite right for the conditions of your problem. The one you are using is a special case where the angle of incidence is normal to the grating. You need to include the angle of incidence in your equation. So your equation would be
    d*(sin(theta(m)) - sin(theta(inc))) =m*lamda. where m = ±1 for first order maxima. Anyway see if that helps.
     
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