Help Solve Physics Problem: Reflection Question

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In summary, to solve the problem, you need to place a mirror on the left wall so that the reflected light from the bulb exactly fills the right wall. You can find the proper height of the mirror by using the law of reflection and connecting the top and bottom of the wall with the mirror image of the source. Additionally, you can determine the distance of the mirror from the ceiling by using similar triangles. Finally, you can find the height of the shadow on the right wall by using the distance between the mirror and the screen and the height of the screen.
  • #1
physicsismydaddy
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Need some help on a practice physics problem.

You need to place a mirror on the left wall, so that the reflected light from the bulb exactly fills the right wall.

ceiling
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3m | |
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_________________________
4m
- the light bulb is 1m away from the left wall, it looks like it is centered.
a. what is the proper height of the mirror?
b. how far below the ceiling should the edge of the mirror be?
c. a 10cm tall screen to the right of the bulb from illuminating the right wall directly, what is the height of the screen's shadow on the right wall?

how I've approached the problem thus far: I started by stating that the angle that the top right corner makes with the mirror's top should be theta reflective and the other angle to the source from the mirror would be theta incidence due to the law of reflection. I'm lost as to where to go from here.
 

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  • #2
physicsismydaddy said:
You need to place a mirror on the left wall, so that the reflected light from the bulb exactly fills the right wall.

how I've approached the problem thus far: I started by stating that the angle that the top right corner makes with the mirror's top should be theta reflective and the other angle to the source from the mirror would be theta incidence due to the law of reflection. I'm lost as to where to go from here.


And you know that theta reflective equals to theta incidence.
You can find the edges of the mirror easily by connecting the top (bottom) of the wall and the mirror image of the source by straight lines. See the figure attached.

ehild
 
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  • #3


a. To find the proper height of the mirror, we can use the law of reflection which states that the angle of incidence (θi) is equal to the angle of reflection (θr). Since the light bulb is 1m away from the left wall and it appears to be centered, we can assume that the angle of incidence is 45 degrees (θi = 45 degrees). This means that the angle of reflection is also 45 degrees (θr = 45 degrees).

Now, we can use trigonometry to find the height of the mirror. We know that the distance from the left wall to the ceiling is 3m and the distance from the light bulb to the left wall is also 3m. Using the tangent function, we can set up the following equation:

tan 45 degrees = height of mirror / 3m

Solving for the height of the mirror, we get:

height of mirror = 3m * tan 45 degrees = 3m * 1 = 3m

So, the proper height of the mirror should be 3m.

b. To find how far below the ceiling the edge of the mirror should be, we can use the same trigonometric approach. Since the angle of reflection is 45 degrees, we can use the tangent function again to set up the following equation:

tan 45 degrees = distance from ceiling to edge of mirror / 3m

Solving for the distance from ceiling to edge of mirror, we get:

distance from ceiling to edge of mirror = 3m * tan 45 degrees = 3m * 1 = 3m

So, the edge of the mirror should be 3m below the ceiling.

c. To find the height of the screen's shadow on the right wall, we can use similar triangles. The height of the screen is 10cm and the distance from the light bulb to the right wall is 4m. This creates a triangle with a base of 4m and a height of 10cm.

We can use the ratio of the two sides of this triangle to find the height of the shadow. This ratio is equal to the ratio of the two sides of the larger triangle created by the light bulb, mirror, and right wall.

So, we can set up the following equation:

height of shadow / 4m = 10cm / 3
 

1. What is a reflection question in physics?

A reflection question in physics is a type of problem that involves understanding the behavior and properties of light when it strikes a surface and bounces off. This can include concepts such as the law of reflection, angle of incidence, and angle of reflection.

2. How do I approach solving a reflection question in physics?

First, make sure you understand the basic principles of reflection, such as the law of reflection and the different types of angles involved. Then, carefully read the question and identify what is being asked. Draw a diagram if necessary and use the appropriate equations to solve for the unknown variables.

3. Can you give an example of a reflection question in physics?

Sure! An example of a reflection question in physics could be: "A ray of light strikes a mirror at an angle of 30 degrees. If the angle of reflection is 30 degrees, what is the angle of incidence?" To solve this, we would use the law of reflection: angle of incidence = angle of reflection. Therefore, the angle of incidence in this case would also be 30 degrees.

4. What are some common mistakes to avoid when solving reflection questions in physics?

One common mistake is mixing up the angle of incidence and angle of reflection. Remember, the angle of incidence is the angle at which the light hits the surface and the angle of reflection is the angle at which it bounces off. Also, be careful when using equations and make sure you are using the correct formula for the specific scenario.

5. How can I check my solution to a reflection question in physics?

To check your solution, you can use the law of reflection and make sure that the angle of incidence and angle of reflection are equal. You can also try plugging your values back into the original equation and see if it gives you the correct answer. If possible, you can also compare your solution with a classmate or ask your teacher for feedback.

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