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Refracted Ray help

  1. Nov 5, 2014 #1
    1.
    I figured out the first few, I just can't get the last one!!

    -The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.4° what is the index of refraction of the material?
    1.54

    -A light ray strikes this material (from air) at an angle of 37.9° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees).
    37.9 deg

    -Calculate the angle of the refracted ray (in degrees).

    23.5 deg

    Assume now that the light ray exits the material. It strikes the material-air boundary at an angle of 37.9° with respect to the normal. What is the angle of the refracted ray?
    ??????

    2. Relevant equations
    Refractive index x sin (theta)

    3. The attempt at a solution

    1.54 x sin (37.9) = .945999


    What am I doing wrong?
     
  2. jcsd
  3. Nov 5, 2014 #2
    Do you know Snell's law? What you wrote there is incomplete. Wrote the complete law.
     
  4. Nov 5, 2014 #3
    I figured it out. Thanks
     
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