# Refracted Ray help

1. Nov 5, 2014

### carpelumen

1.
I figured out the first few, I just can't get the last one!!

-The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.4° what is the index of refraction of the material?
1.54

-A light ray strikes this material (from air) at an angle of 37.9° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees).
37.9 deg

-Calculate the angle of the refracted ray (in degrees).

23.5 deg

Assume now that the light ray exits the material. It strikes the material-air boundary at an angle of 37.9° with respect to the normal. What is the angle of the refracted ray?
??????

2. Relevant equations
Refractive index x sin (theta)

3. The attempt at a solution

1.54 x sin (37.9) = .945999

What am I doing wrong?

2. Nov 5, 2014

### nasu

Do you know Snell's law? What you wrote there is incomplete. Wrote the complete law.

3. Nov 5, 2014

### carpelumen

I figured it out. Thanks