1. I figured out the first few, I just can't get the last one!! -The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.4° what is the index of refraction of the material? 1.54 -A light ray strikes this material (from air) at an angle of 37.9° with respect to the normal of the surface. Calculate the angle of the reflected ray (in degrees). 37.9 deg -Calculate the angle of the refracted ray (in degrees). 23.5 deg Assume now that the light ray exits the material. It strikes the material-air boundary at an angle of 37.9° with respect to the normal. What is the angle of the refracted ray? ?????? 2. Relevant equations Refractive index x sin (theta) 3. The attempt at a solution 1.54 x sin (37.9) = .945999 What am I doing wrong?