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Refraction of light in a pool

  • Thread starter 21385
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  • #1
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Homework Statement


At the shallow end of a swimming pool, the water is 70.0 cm deep. The diameter of the cone of the light emerging from the water into the air above, emitted by a light source 10.0 cm in diameter at the bottom of the pool and measured by an observer on the edge of the pool 2.50 m away, is
a) 1.60 m
b) 1.70 m
c) 1.75 m
d) 1.80 m


Homework Equations


nsin(angle)=nsin(angle)
nsin(criticalangle)=nsin90


The Attempt at a Solution


I am really confused, can anybody help me? I don't know where to start.

Thanks
 

Answers and Replies

  • #2
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i don't sure the situation is clear. how tall is the observer?
 
  • #3
Doc Al
Mentor
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This is a critical angle problem. Draw a diagram of the light (at the bottom of the pool) being emitted at all angles. Figure out the maximum angle that will be refracted--anything greater will just be reflected by the water surface--and use that to calculate the diameter of the cone.
 

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