(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Refresher on Derivatives

I feel rather dumb asking this but I could use a quick refresher on some parts of derivatives since for the past months I have been solely working on integrals and known cross sections so suddenly switching back has left my brain reeling.

The main question I need explained is how do you take a derivative of [tex]-(t + 1)sin(\frac{t^2}{2})[/tex]

I remember a trick my AP teacher told me of 1D2 + 2D1 meaning take the first part muliplied by the derivative of the second plus the second multiplied by the derivative of the first. The problem is, I don't remember how to take the derivatve of (t^2)/2

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# Refresher on Derivatives

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