Refrigerator and Heat Pump

  • Thread starter fiziks09
  • Start date
  • #1
fiziks09
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Homework Statement


A freezer has a coefficient of performance of 6.30. It is advertised as using electricity at a rate of 457kWh/yr.
a)On average how much energy does it use in a single day?
b) What maximum mass of water at 20.0 degree celsius could the freezer freeze in a single day.

NOTE: One kilowatt hour is an amount of energy equal to running a 1-kW appliance for one hour


Homework Equations


COP = Q / W


The Attempt at a Solution


I tried to use comparison like so;

if 457kWh is the rate for 365 days
then xkWh is the rate for 1 day

This gives me 1.25 J which is very wrong.

Please can i get clues on how to start or what to do on the "A" part of the question. It's really twisting my head..thanks a lot for your help..
 

Answers and Replies

  • #2
I like Serena
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Hi fiziks09! :smile:

What you have is 1.25 kWh, which is 1250 Watt times 1 hour.
This is not 1.25 J, which is 1.25 Watt times 1 second.

You'll need to convert the unit...
 
  • #3
fiziks09
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okay..
but converting the unit still gives a wrong answer...
 
  • #4
I like Serena
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How did you convert it?
 
  • #5
fiziks09
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okay i might have misunderstood. I'm so sorry..what conversion is being made?
is it from kWh to Joules or what? if so how so??
 
  • #6
fiziks09
28
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Allright i got it now..
since 1kWh = 3.6MJ (which is 3600000J)

1.25kWh X 36000000 = 4.5 X 10^6 Joules..

thanks for the help...
 
  • #7
I like Serena
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Good! :smile:
 

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