A 5.0 kg, 60-cm diameter disk rotates on an axle passing through one edge. The axle is parallel to the floor. The cylinder is held with the center of mass at the same height as the axle, then released.
a. What is the cylinder's initial angular Acceleration?
b*. What is the cylinder's angular Velocity when it is directly below the axle?
The Attempt at a Solution
Part A: I utilized the Parallel axis theorem because it was rotating off the center of mass.
I=Icm+MD^2->[I of disc] (1/2 (5)(0.3)^2) + 5(.3)^2= 0.675
For the torque: T=R*F->(0.3)(5*9.8)=14.7
14.7/0.675= 21.78 Rad/S^2
Can someone tell me if I did something incorrect? Also:
Part B: I have no idea where to start. This is where I really need help.