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Regarding force summation

  1. Apr 7, 2014 #1
    1. The problem statement, all variables and given/known data
    60f83f1915e83c016d92ecc2c7e13a1b.png

    Find the magnitude and direction of a resultant force equivalent to the given force system and locate its point of application on the slab.

    3. The attempt at a solution
    So I summed the forces to get -1400 N, or a 1400 N force downward (the book agrees with that). Why is the resultant force going upward? It seems to me that they have printed a 1400 N force upward. I have no issue with the rest of the problem, but was hoping someone could explain to me why Fr is going upward.
     
    Last edited: Apr 7, 2014
  2. jcsd
  3. Apr 7, 2014 #2
    It's just schematic and general. It's not meant to represent exactly the solution to this specific problem.

    Chet
     
  4. Apr 7, 2014 #3
    Thank you for the response.
    In the summary of the conclusion they say a Force of Fr = 1400 N is placed at P(x,y). So I assumed they wanted a positive force.
     
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