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Regarding steady state current

  1. Jan 11, 2009 #1
    1. The problem statement, all variables and given/known data
    Hello,
    I've just done a paper on basic electronics and I'm stuck on the last question. I don't know how to go about doing the question.

    [​IMG]

    2. Relevant equations
    N/A


    3. The attempt at a solution
    I don't know how to even start with the question. I've tried googling "steady state current", "steady state current circuit", "how to .." and so on but nothing relevant seems to be coming up. I've also tried to ask my friends who are a year ahead and they can't remember how to do it.
     
  2. jcsd
  3. Jan 11, 2009 #2
    I assume steady state meaning DC which means inductor is a short circuit, it become 0ohm and disappeared. Cap become an open and the 30ohm on the right disappeared. So you only have a 12V battery connecting to a 30ohm and a 12ohm in series which give a total of 48ohm

    So the current I=V/R = 12/48=0.25A!!!

    Is this a trick question?
     
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