# Regarding z0 interactions

AdvaitDhingra
If there are no flavor changing z0 weak interactions, how do we even know that the particle exists? I thought that we could only tell which particle was exchanged by the particles it decays into. Is this wrong?

## Answers and Replies

Staff Emeritus
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How would the absence of flavour changing Z0 interactions preclude the knowledge of its existence? You will still see the decays to particle-antiparticle pairs just the same. The cleanest way of producing Z0 is to collide electrons with positrons at the Z0 resonance.

ohwilleke, vanhees71, Vanadium 50 and 1 other person
AdvaitDhingra
How would the absence of flavour changing Z0 interactions preclude the knowledge of its existence? You will still see the decays to particle-antiparticle pairs just the same. The cleanest way of producing Z0 is to collide electrons with positrons at the Z0 resonance.
Oh ok. So a z0 Boson interaction is one where charge is conserved? (since the z0 carries no charge)

vanhees71
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Do you see a peak (Z) or not (no Z)?

ohwilleke, vanhees71 and AdvaitDhingra
Mentor
Charge is always conserved.

Flavor-changing Z interactions would allow e.g. electron plus antimuon to Z, or Z to these two particles. We don't observe that decay (experimental upper limit is ~10-6), but of course we see the flavor-conserving electron+positron->Z production (that's what we can actually collide in colliders) and the equally flavor-conserving decays to quark plus matching antiquark.

ohwilleke