Regarding z0 interactions

  • #1
If there are no flavor changing z0 weak interactions, how do we even know that the particle exists? I thought that we could only tell which particle was exchanged by the particles it decays into. Is this wrong?
 

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  • #2
Orodruin
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How would the absence of flavour changing Z0 interactions preclude the knowledge of its existence? You will still see the decays to particle-antiparticle pairs just the same. The cleanest way of producing Z0 is to collide electrons with positrons at the Z0 resonance.
 
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  • #3
How would the absence of flavour changing Z0 interactions preclude the knowledge of its existence? You will still see the decays to particle-antiparticle pairs just the same. The cleanest way of producing Z0 is to collide electrons with positrons at the Z0 resonance.
Oh ok. So a z0 Boson interaction is one where charge is conserved? (since the z0 carries no charge)
 
  • #4
Vanadium 50
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Do you see a peak (Z) or not (no Z)?

1618312813823.png
 
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  • #6
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Charge is always conserved.

Flavor-changing Z interactions would allow e.g. electron plus antimuon to Z, or Z to these two particles. We don't observe that decay (experimental upper limit is ~10-6), but of course we see the flavor-conserving electron+positron->Z production (that's what we can actually collide in colliders) and the equally flavor-conserving decays to quark plus matching antiquark.
 

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