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Related rates help

  1. Oct 5, 2013 #1
    1. Assume that the radius r of a sphere is expanding at a rate of 50 cm/min. The volume of a sphere is V= 4/3 πr^3 and its surface area is 4πr^2.Determine the rate of change of volume when r = 13 cm



    2. I tried d/dr=8*13*50*pi



    3. 5200pi but is wrong
     
  2. jcsd
  3. Oct 5, 2013 #2

    haruspex

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    Pls post your reasoning/working to obtain that expression for (I presume you meant) dV/dr.
     
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