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V=(pi)r^2h, dV/dt = 0.2, r = 0.8 ?

Can anyone give me a hand in getting this one started?

- Thread starter Mitchtwitchita
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- #1

- 190

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V=(pi)r^2h, dV/dt = 0.2, r = 0.8 ?

Can anyone give me a hand in getting this one started?

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HallsofIvy

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- #3

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0.2 = (pi)(o.8)^2*dh/dt

dh/dt =0.0995 ?

Hypothetically, how would you solve for volume if the rates of change of the height and radii are given, as well as the radius and height when the derivative would seem to cancel the h in the equation?

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