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Homework Help: Related Rates Problem

  1. Jun 29, 2008 #1
    1. The problem statement, all variables and given/known data
    A balloon is rising at a constant speed of 5 ft/s. A boy is cycling along a straight road at a speed of 15 ft/s. When he passes under the balloon, it is 45 ft above him. How fast is the distance between the boy and the balloon increasing 3 seconds later.


    2. Relevant equations
    dx/dt=15 ft/s
    dy/dt=5 ft/s
    c2=x2+y2

    3. The attempt at a solution
    2c dc/dt = 2x dx/dt + 2y dy/dt
    c(dc/dt) = x(dx/dt) + y(dy/dt)
    c(dc/dt) = x(15) + y(5)
    c(dc/dt) = 15x + 5y
    My first problem is: Is the 45ft x or y?
     
  2. jcsd
  3. Jun 29, 2008 #2

    tiny-tim

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    Welcome to PF!

    Hi cmajor47! Welcome to PF! :smile:

    45 ft is the value of y at time 0 (and 0 ft is the value of x at that time).

    In your equation, c(dc/dt) = 15x + 5y, c x and y must be the values at time 3. :smile:
     
  4. Jun 29, 2008 #3

    HallsofIvy

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    There was NO "x" or "y" in the original problem! Since you were the one who wrote dx/dt= 5 ft/s and were told "A balloon is rising at a constant speed of 5 ft/s." I guess you were taking x to be the height of the ballon at any given time. What was the height of the ballon at the time in question?
     
  5. Jun 30, 2008 #4
    Don't I have to assign a letter value to each piece of information? Did I assign them correctly?
     
  6. Jun 30, 2008 #5

    HallsofIvy

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    No one can tell you what letters are "correct"- it is entirely your choice. You just have to be consistent.

    What did YOU choose x and y to represent when you set up the equation? What are values of the quantities represented by x and y at the point in time in question?
     
  7. Jun 30, 2008 #6
    I realized how to solve the problem. Thanks to everyone for their help.
     
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