Could someone verify my answer for this question? 13m ladder is leaning against a wall. If the top of the ladder slips down the wall at a rate of 2m/s. How fast will the foot be moving away from the wall when the top is 5m from the ground? My answer: use pythagoras to set up equation x^2 + y^2 = 13^2 Then I differentiate this implicitly and get the equation 2x dx/dt + 2y dy/t = 0 Then I fill in the values and get 5/6 m/s. Is this correct?