1. The problem statement, all variables and given/known data A child weighs 34 Kg is seated on a seesaw. While a child who weighs 40 kg is situated on tghe opposite end of the seesaw. The functio B(x)= 34x / 40 gives the distance that the 40 kg child must sit from the center of the seesaw when the 34 kg child sits x meters from the center. The seesaw is 9m long find the average rate of change in distance as the lighter childs distance changes from 1.5m to 2.5meters. 2. Relevant equations I used the quotient rule to find the derivative of the function. Which turns out to be 68 / 80. 3. The attempt at a solution I used the quotient rule to fine the instanenous rate of change which turns out to be B'(x)= 68/80. I dont know how to takle the average rate of change.