Calculating Torpedo Angle & Travel Time to Hit Carrier 5 Miles N

Thread starter rastakitty
Start date Aug 1, 2007
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Angle Carrier Time Travel

In summary, the angle and travel time for a torpedo to hit a carrier 5 miles north can be calculated using trigonometry and various equations. The necessary information includes the distance between the torpedo and carrier, the torpedo's speed, and any external factors that may affect its trajectory. These calculations can vary depending on the type of torpedo being used, and it is important to have accurate measurements and use the appropriate equations to obtain accurate results.

Aug 1, 2007

rastakitty

need help.. carrier 5 miles N of sub traveling E @ 3mins/hr. sub has torpedoe travel @ 40 knots. what is the angle and distance travel of torpedoe to hit carrier, what is travel time . with respect to original sighting

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Aug 2, 2007

mathwonk

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Homework Helper

pythagorean theorem gives quadratic equation in lengths. then diff lengths wrt t.

Aug 2, 2007

HallsofIvy

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Homework Helper

Obviously a homework problem, obviously no work shown.

1. How do you calculate the angle for a torpedo to hit a carrier 5 miles north?

The angle for a torpedo to hit a carrier 5 miles north can be calculated using trigonometry. First, determine the distance between the torpedo and the carrier, which in this case is 5 miles. Then, measure the distance between the torpedo and the surface of the water, as well as the distance between the torpedo and the carrier's keel. These measurements can then be used to calculate the angle using the tangent function.

2. What information is needed to accurately calculate the travel time for a torpedo to hit a carrier 5 miles north?

In order to accurately calculate the travel time for a torpedo to hit a carrier 5 miles north, you will need to know the speed of the torpedo, the distance between the torpedo and the carrier, and any external factors that may affect the torpedo's trajectory, such as wind or currents. It is also important to have accurate measurements of the torpedo's starting position and the carrier's position.

3. How can external factors, such as wind and currents, affect the travel time for a torpedo to hit a carrier 5 miles north?

External factors can greatly affect the travel time for a torpedo to hit a carrier 5 miles north. Wind and currents can alter the trajectory of the torpedo, causing it to either speed up or slow down, and potentially miss the target. It is important to take these factors into account when calculating the travel time for a torpedo.

4. Can the angle and travel time for a torpedo to hit a carrier 5 miles north be calculated for different types of torpedoes?

Yes, the angle and travel time for a torpedo to hit a carrier 5 miles north can be calculated for different types of torpedoes. However, the calculations may vary depending on the speed and characteristics of the specific torpedo being used. It is important to have accurate information about the torpedo being used in order to calculate these values correctly.

5. Is there a certain formula or equation that can be used to calculate the angle and travel time for a torpedo to hit a carrier 5 miles north?

Yes, there are several equations and formulas that can be used to calculate the angle and travel time for a torpedo to hit a carrier 5 miles north. These include the tangent function for calculating the angle, as well as equations for calculating the distance and time based on the torpedo's speed and the distance between the torpedo and the carrier. It is important to use the appropriate equations and have accurate measurements in order to obtain accurate results.