Suppose that Y=2((x^2)-3x) and dx/dt = 2
Find dy/dt when x=3
the only calc is taking the derivative of the equation, i am wondering if i am doing the whole problem right.
The Attempt at a Solution
dy/dx = 4x-6
find the equation for x=3 and multiply in 2 for the rate of change of time
I think my answer goes back to the clac. I don't know what number i am supposed to plug in for X, i know it has to do when what X equals at dy/dt and the rate of chage of X over time.