1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Related rates

  1. May 11, 2016 #1
    1. The problem statement, all variables and given/known data
    An RAAF Roulette aeroplane is performing a low fly over at an air show. Under the current wind conditions its top speed is 450 km/hour, and it will fly directly over the crowd at an altitude of only h=340metres approaching from the North. When the aeroplane is only x=180metres horizontally from a person in the crowd looking North, how fast are they rotating their head upwards to keep the aeroplane in the centre of their vision?

    You should neglect the height of the person in your calculations. Give your answer in radians per second, either exactly or correct to three decimal places.

    2. Relevant equations

    would I need to use pythagoras to solve this?
    Does this mean that dx/dt is 450?

    Any help would be much appreciated
  2. jcsd
  3. May 11, 2016 #2


    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    You will need to use trig and calculus. I would recommend working ent irely algebraically (no numbers!) until the final step, and don't forget to convert to standard units.
  4. May 11, 2016 #3
    does this mean:





    what would I so now?
  5. May 11, 2016 #4


    User Avatar
    Homework Helper
    Gold Member

    You are asked to find how fast the angle of vision is changing(w.r.t.ground, since height of the person is neglected). Form an equation which relates this angle to the given quantities. That's where trigonometry comes into picture. Start with a diagram. It will make a lot of things clear for you.
    Last edited: May 11, 2016
  6. May 11, 2016 #5


    Staff: Mentor

    No, this makes no sense. From ##s^2## to 2s, you are apparently differentiating with respect to s, but from ##h^2## to 2h, you're differentiating with respect to h. You are also differentiating ##x^2## with respect to x.

    In other words, ##\frac{d s^2}{ds} = 2s## and ##\frac{d h^2}{dh} = 2h##. If you differentiate both sides of an equation, the differentiation must be done with the same variable.

    What you're missing is that s, h, and t are all functions of t.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted