Assuming there are five identical light bulbs. Light bulb C and D are in a series connection. C and D are in a parallel connection with E. Light Bulb A and B are in a parallel connection. The two parallel connections are wired in a series connection. What would be their relative brightness? I'm thinking that A=B=E=C+D(adsbygoogle = window.adsbygoogle || []).push({});

********************

|----power---------------|

|*******************|

|*******************|

|**|--A--|***|-C-D-|**|

|---|****|----|****|---|

***|--B--|***|--E--|***

********************

in a parallel connection, It=I1+I2, therefore, A=B. In a seriese connection, The total current equals the individual currents, so C=D. Back to the parallel connection, C+D=E. In a series, they are all equal, so (A+B)=(E+C+D). Therefore...A=B=E=C+D. My friend said that it might be: C^D<A^B<E

Any suggestions?

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# Relative brightness

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