(adsbygoogle = window.adsbygoogle || []).push({}); 1. Collagen fiber is stressed with 12 N force. The cross-sectional area of the fiber is 3 mm2, its coefficient of elasticity is 500 MPa. Give the percentage of relative extension.

I think i have found the correct equation but i cant seem to find the rigth answer wich is suposed to be 0.8% but i always end up with 8*10^-4..

2. Relevant equations

F/A=E Δl/l

3. The attempt at a solution

12N/(0,003m^2 * 5*10^6 Pa)

and then I get a result of 8*10^-4, and I am stuck.. I belive there is something fundamental I have missed but I can't seem to find it.. Thanks in advance!

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# Relative extension

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