- #1

greg997

- 109

- 2

The problem i have seems very easy but i am just not sure.

There is a number of calls per hour ( from 8-12) received by customer service.

Mon 1,3,0,5

Wed 2,0,0,1

Fr 4,2,1,0

So now what is the relative frequncy for n calls per hour? Total number of calls is 19. So for n=5 it is 1/19 =5.2%. For n=2 it is 2/19= 10.5%. And for n=0 it is 4/19 = 21%?? Is it right with the zero?

Is the mean value of calls 19/12=1.5 per hour?

To calculate the probability of having 2 calls is it enough to stick the mean value and the 2 into the poissons formula?

Would appreciate the help.

There is a number of calls per hour ( from 8-12) received by customer service.

Mon 1,3,0,5

Wed 2,0,0,1

Fr 4,2,1,0

So now what is the relative frequncy for n calls per hour? Total number of calls is 19. So for n=5 it is 1/19 =5.2%. For n=2 it is 2/19= 10.5%. And for n=0 it is 4/19 = 21%?? Is it right with the zero?

Is the mean value of calls 19/12=1.5 per hour?

To calculate the probability of having 2 calls is it enough to stick the mean value and the 2 into the poissons formula?

Would appreciate the help.

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