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Relative Maximum

  1. Dec 18, 2003 #1
    For what value of k will [tex] x + \frac{k}{x}[/tex] have a relative maximum at x= -2?
  2. jcsd
  3. Dec 18, 2003 #2


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    Looks straight forward to me.

    In order to have a critical point at all we must have f'(x)= 0.
    What is the derivative of f? In order that there be a critical point at x= -2, put x= -2 in f'(x)= 0 and solve for k.
    Last edited: Dec 18, 2003
  4. Dec 18, 2003 #3
    Hey Tandoori
    Most of ur Qs are straightforward

    So it is better if u show ur attempt also
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