# Homework Help: Relative Momentum

1. May 27, 2012

### dlucia

I have been getting rather confused with rest mass, m0. here's the problem.

A particle intially has a speed of 0.58c. A) At what speed does it momentum increase by 1%. B) At 10%, and C) At 100%.

I have set it up as p=γm0v....
then γ=1/ sqrt[1=(0.58)^2

but dont know what to do any further. Thanks

2. May 28, 2012

### tiny-tim

welcome to pf!

hi dlucia! welcome to pf!

(try using the X2 and X2 buttons just above the Reply box )

what's the difficulty?

you have momentum = p = po/√(1 - (v/c)2),

so just put p/po = A) 1.01 B) 1.1 C) 2, and solve

3. May 28, 2012

### Staff: Mentor

Shouldn't it be

$\frac{(v/c) γ(v/c)}{0.58 γ(0.58)}$ = 1.01

$\frac{(v/c) γ(v/c)}{0.58 γ(0.58)}$ = 1.1

$\frac{(v/c) γ(v/c)}{0.58 γ(0.58)}$ = 2.0

Chet

Last edited: May 28, 2012