(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Car A's velocity varies as Va=3t^2i+ 3tj

Car B's velocity varies as Vb= -4ti+ 4t^2j

Both car's start at t=0.

a) Find the position of Car A with respect to Car B at t=1 second.

b) Find the velocity of Car B with respecto Car A at t=2.

3. The attempt at a solution

a) I began by finding the antiderivative of Va and Vb.

I got v'(A)=t^3i+ 3/2t^2iand

v'(B) = -2t^2i+ 4/3t^3

Then I plugged in 1 for t and subtracted Car A - Car B.

I got 3i- 1/6j

Did I do that right?

b) I basically did the same thing except I used to orginial equations, plugged in 2 for t, abd subtracted Car B- Car A.

I came up with 4i- 24j

Did I do those problems correctly?

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# Homework Help: Relative Motion and Vectors

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