A ship is traveling at 8.0 m/s at an angle of 50 degrees north of east relative to the water. The water moves at 3 m/s due south relative to the shore.
a- Determine the velocity of the ship relative to the shore.
b- A person running along the deck of the ship moves at 2 m/s at 45 degrees south of west. What is his velocity relative to the shore?
V= (Va cos angle a + Vb cos angle b) i-hat + (Va sin angle a + Vb sin angle b) j-hat
The Attempt at a Solution
(8cos50 + 3 cos -90) i-hat + (8sin 50 + 3 sin -90) j-hat =
5.14 m/s i-hat + -3.12 m/s j-hat
I am confused about part b. Do I need to factor in the motion of the ship that the person is on? Or do I combine his velocity with that of the water since it is measured relative to the shore?