A swimmer crossing a river proceeds at an absolute speed of 2.5 m/s on a course oriented at a 45degree angle to the 1 m/s current. Given that the absolute velocity of the swimmer is equal to the vector sum of the velocity of the current and the velocity of the swimmer with respect to the current what is the magnitude and direction of the velcoity of the swimmer with respect to the current? So: 1. absolute speed = resulatant = 2.5 m/s 2. Known: Vc = 1 m/s --> Vs = 2.5 m/s @ 45 degree angle Vs= Vc + Vs/Vc Im stuck with how I work out the Velocity of the swimmer in respect to the velcoity of the current. I tried using R2=a2 + b2 but they didnt work any suggestion where to start?