1. The problem statement, all variables and given/known data Two ships, A and B, leave port at the same time. Ship A travels northwest at 22 knots and ship B travels at 29 knots in a direction 40° west of south. (1 knot = 1 nautical mile per hour; see Appendix D.) (a) What is the magnitude the velocity of ship A relative to B? _____knots (b) What is the direction of the velocity of ship A relative to B? _____° east of north (c) After what time will the ships be 125 nautical miles apart? ____h (d) What will be the bearing of B (the direction of B's position) relative to A at that time? _____° west of south 2. Relevant equations Velocity of A=Velocity of B+Velocity of A with respect to be or V_a=V_b+V_ab 3. The attempt at a solution I've tried to use the initial speeds: 22=V_ab+29 V_ab=-7 so the magnitude would be 7 which is an incorrect answer I've also tried using the vector equations: V_a=(-15.55i+15.55j) or (22cos135i+22sin135j)( I used 45 degrees+90 to get the sign with respect to a y axis that has positive north, and x axis with positive east) V_b=(-22.22i+18.64j) or (29sin310i+29cos310j)(I used 40+270 to get the correct sign with respect to above names axis) Splitting the two equations I get: -15.55=V_abx-22.22 and 15.55=V_aby+18.64 therefore: V_abx=-6.67 and V_aby=-3.09 so V_ab is (-6.67i-3.09j)and the magnitude of this vector is: 7.35 however I've used all but one try left so I wanted to make sure this was the correct answer. Is this the proper way to solve this problem?