Two ships, A and B, leave port at the same time. Ship A travels northwest at 19 knots and ship B travels at 28 knots in a direction 40° west of south. (1 knot = 1 nautical mile per hour; see Appendix D.) (a) What is the magnitude the velocity of ship A relative to B? 35.181 knots (b) What is the direction of the velocity of ship A relative to B? _____ ° east of north (c) After what time will the ships be 110 nautical miles apart? _____ h (d) What will be the bearing of B (the direction of B's position) relative to A at that time? _____° west of south 2. Vab = Vas - Vbs Vas = -19cos45 + 19sin45 = -13.435i + 13.435j Vbs = -28cos50 - 28sin50 = -17.998i - 21.449j Vab = 4.563i + 34.884j magnitude of Vab = 35.181 arctan(34.884/4.563) = 82.548 degrees 3. For some reason, this value for the angle (which I'm trying to find for part b) is wrong. Any ideas on what I did wrong guys?