Please..give It A Try "Ship A is located 4 km north and 2.5 km east of ship B. Ship A has a velocity of 22km/h towards the south and ship B has a velociy of 40 km/h in a direction of 37(degrees) north of east. A)what is the velocity of A relative to B B)write an expression for the position of A relative to B as a function of t, where t is equal to 0. ***C) at what time is the separation between the ships least? Ive completed A and B..but i have no idea where to start for C..Can anyone help? wellllllllll; first i found the point of A relative to B= ...ans = [32km/h(t) + 2.5 km]i + [2.0km/h(t) + 4.0km]j im guessing it has something to do with a max-min problem..but im not sure where to start..i could do trial and error..but there has to be a simpler way..