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Relative position and velocity question (Two dimensions)
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[QUOTE="kappakeepo, post: 4981928, member: 539225"] Thanks for your reply. $$\vec r_{bg} = (\vec u_{cg}t)\hat\imath + (\vec u_{bc}t - 0.5gt^2)\hat\jmath$$ My only question is how do I solve the part "How much time is the ball in the air according to the man on the ground?" I can't let $$\vec r_{bg} = 0$$ because that would be wrong obviously because here my ground is the person. And since if that is equals to 0 it would imply they are both touching/colliding each other. I only want to find how long is the ball on air i.e. the $$\hat\jmath = 0$$ I stated in my solutions that my equation ignored the unit $$\hat\imath \implies \vec r_{bg} = 0 + (\vec u_{bc}t - 0.5gt^2)\hat\jmath$$ and then solving it but I have no idea if that's acceptable. It looks wrong to me anyway still lol. Is there any better way to solve it? =) [/QUOTE]
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Introductory Physics Homework Help
Relative position and velocity question (Two dimensions)
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