# Relative vector

1. Nov 3, 2012

### wuki1

1. The problem statement, all variables and given/known data
an airplane, whose air speed is 580km/h, is supposed to fly in a straight path 38N of E. But a steady 72km/h wind is blowing from the north. In what direction should the plane head? i know the answer is 43.6 N of E but i am not completely sure how to get it

2. Relevant equations
so i think i have to use 580cos(38) and 580sin(38) but when i do it this way it does not work.
My friend told me to use sin/72=sin(38+90)/580 which does work but i am not completely sure if thats what i should use

3. The attempt at a solution
before i used 580cos(38) 580sin(38) 72cos(270) and 72sin(270) but i got something like 43.2 instead of 43.6 if somebody could explain it to me it would help. thank you

2. Nov 3, 2012

### Staff: Mentor

Did you draw a sketch? You can add the velocity of the airplane and the wind velocity (as vectors) to get the effective velocity and its direction. You can use that diagram to get the correct formula.

3. Nov 3, 2012

### wuki1

the problem is tho that you only have the velocity of the plane no? because you do not have its direction that is what you are trying to get the direction it should go in because while its supposed to be at a 38 angle the south wind is changing its direction. so when i tried doing it that way i did
580cos(38)=457.0462371
580sin(38) + 720=429.0836557
and if you then do arctan you get 43.2 which is not correct because it an angle of 43.6
while you can use the law of sines i am trying how to figure it out using the vector components

4. Nov 4, 2012

### haruspex

580 cos(38) etc. cannot be interesting because the 580 is the plane's speed relative to the air but the 38 is not the plane's heading relative to the air. Put in an unknown for the relative heading and obtain some equations.

5. Nov 4, 2012

### wuki1

so would the equation look something like this
580^2=(72+xsin(38))^2+(xcos(38))^2? if so how would one go abut solving it because i am having trouble figuring this out.

6. Nov 4, 2012

### haruspex

Actually, I said to introduce an unknown for the heading. That's an angle. But you've introduced x as the net speed, which is fine. And your equation looks right.
Can you not expand the squarings on the RHS to obtain a quadratic in x?