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Relativistic invariance

  1. Apr 18, 2007 #1
    In Feynman lectures in physics v2 28-6, Feynman points out that we can add a constant times [itex]\phi[/itex] to D'Alembertian without distrupting the relativistic invariance. How and why?? Can someone work out a mathematical proof?

    Thanks in advance.
     
  2. jcsd
  3. Apr 18, 2007 #2
    The sum of two invariant quantities is an invariant quantity.
     
  4. Apr 19, 2007 #3

    Mentz114

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    Gold Member

    The derivative of a constant wrt any variable is zero.
     
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