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Relativistic mechanics

  1. Jan 31, 2010 #1
  2. jcsd
  3. Jan 31, 2010 #2

    gabbagabbahey

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    It's difficult to read scanned images like this. Next time, please just make the effort to type out the relavant information yourself.

    Anyways, are you referring to the equation, [tex]\mathcal{E}^2(1-V^2\cos^2\theta)-2\mathcal{E}\mathcal{E}_0\sqrt{1-V^2}+\mathcal{E}_0^2(1-V^2)+V^2m^2\cos^2\theta=0[/itex] ?

    If so, just use the quadratic formula and post your work if you get stuck.
     
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