# Relativistic mechanics

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2. ### gabbagabbahey

5,015
It's difficult to read scanned images like this. Next time, please just make the effort to type out the relavant information yourself.

Anyways, are you referring to the equation, [tex]\mathcal{E}^2(1-V^2\cos^2\theta)-2\mathcal{E}\mathcal{E}_0\sqrt{1-V^2}+\mathcal{E}_0^2(1-V^2)+V^2m^2\cos^2\theta=0[/itex] ?

If so, just use the quadratic formula and post your work if you get stuck.