How Is Momentum Calculated for a Decomposing Particle in Relativistic Physics?

In summary, the momentum of the particle with mass Q after the decay of a particle with mass M and initial velocity of 0 is given by Q*g*v, where v is the velocity of the particle in terms of M, Q, and c. The conservation of energy and momentum apply in this situation, with the total momentum being zero after the decay. The center of mass plays a role in determining the velocity and momentum of the particles, with the massless particle and Q particle having equal and opposite momenta.
  • #1
supercali
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[SOLVED] relativistic momentum

Homework Statement


a particle with mass M and v=0 decomposes to a massless particle and another particle with the mass Q.
find the momentum of the Q particle

Homework Equations


[tex]E^2_{cm}=m^2c^4=(\sum{E})^2-(\sum{P})^2c^2[/tex]


The Attempt at a Solution


i tried using that equation and also tried to do some equations with the conservation of energy and momentum but i just can't figure it out
please help if you can
thanks
and also if you can explain to me the whole deal with center of mass in relativistic momentum and energy
when does the conservation of energy apply?
what happens in the center of the mass as oppose of out of it?
 
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  • #2
Energy and momentum are always both conserved. So the total momentum after the decay is zero. So the momentum of Q is equal in magnitude to the momentum of the massless particle. Now apply conservation of energy. And apply m^2*c^4=E^2-P^2*c^2 to each particle. You should basically get two equations in two unknowns.
 
  • #3
Suppose p1 is the momentum of the massless particle to the left and p2 is the mom of the particle with rest-mass Q to the right, with speed v. Let g denote gamma(v).

p1=p2=Qgv => Also, from energy consvn,

p1c + Qgc^2 = Mc^2 => (cancel c)
Qgv + Qgc = Mc. From this, the value of v comes out in terms of M, Q and c. Not difficult if you factorize and use compodendo-dividendo. Do the algebra. We get,

v/c = (M^2-Q^2)/(M^2+Q^2). Then,

p2 = Q*g*v, all expressed in terms of M, Q and c.
 

What is relativistic momentum?

Relativistic momentum is a concept in physics that takes into account the effects of special relativity on the momentum of an object. It is a measure of the amount of motion an object has in the direction of its velocity.

How is relativistic momentum different from classical momentum?

Relativistic momentum takes into account the effects of special relativity, such as time dilation and length contraction, on the momentum of an object. It differs from classical momentum, which only considers the mass and velocity of an object.

What is the equation for calculating relativistic momentum?

The equation for calculating relativistic momentum is p = mv/√(1-v^2/c^2), where p is the relativistic momentum, m is the mass of the object, v is the velocity of the object, and c is the speed of light.

How does relativistic momentum change at high velocities?

As an object approaches the speed of light, its relativistic momentum increases significantly. This is due to the effects of special relativity, which cause the object's mass to increase and therefore increase its momentum.

What are the practical applications of relativistic momentum?

Relativistic momentum is an important concept in fields such as particle physics, where objects can travel at high velocities. It is also used in the development of technologies such as particle accelerators and space propulsion systems.

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