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Relativistic wave-vector k

  1. Feb 8, 2014 #1
    Hey guys,

    I regard a relativistic vector:
    $$

    k^\mu =(k^0,k^1,k^2,k^3,)=(\frac{\omega_k}{c}, \vec{k} )

    $$

    What is [itex]|\vec{k}|[/itex] of this vector?
    Is it the same as [itex]k^0[/itex]?

    THX
     
  2. jcsd
  3. Feb 8, 2014 #2

    WannabeNewton

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    Yes it's just given by the dispersion relation.
     
  4. Feb 8, 2014 #3

    Meir Achuz

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    [tex]k_0=\omega/c[/tex].
    [tex]{|\bf k|}^2=k^2_0-m^2,[/tex] and equals [itex]k^2_0[/itex] only if m=0.
     
    Last edited: Feb 8, 2014
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