- #1

- 87

- 0

## Homework Statement

A physics instructor is 22 years older than her student. She decides that instead she would like to be 22 years younger than her student and decides to use special relativity to accomplish this. She jumps in her super rocket travels away from earth for a period of 1 years (as measured by her) and then back to earth for the same period.

a) Ignoring the brief period of acceleration, what is the speed at which the physics teacher is traveling during this time?

vteacher = fraction of c *

.99974 OK

b) In the teacher's reference frame, how far does she travel away from the earth during the first portion of this period?

Δxteacher = light-years *

.99974 OK

c) In the student's reference frame, how far does the teacher travel away from the earth during the first portion of this period?

Δxstudent = light-years

43.8444 NO

## Homework Equations

[itex]\gamma[/itex] = sqrt (1 - v^2/c^2)

d' = d[itex]\gamma[/itex]

## The Attempt at a Solution

I found that the teacher travels at .99974c, pretty easily. Since my v = .99974c, [itex]\gamma[/itex] = .022802.

d' = d[itex]\gamma[/itex]

.99974 ly = d (.022802)

d = 43.844 ly

But it is not fond of that answer and I don't see any other way to go about this.