1. Show that if we transform first in the x-direction and then in the minus x direction with the same speed (v), we end up with the original space-time coordinates. Note: For this problem you will need to apply the transformation equation twice. You will also need to apply the transformations to both x and t. 2. Relevant equations x' = \gamma(x-Vt) y' = y z' = z t' = \gamma(t-(Vx)/c^2)) 3. The attempt at a solution I attempted to plug in -x into the x for x' and then plug in x' whenever I found an x. However, this didn't get me far.