- #1
Inconsistency
- 2
- 0
Hello,
1. Show that a free electron in a vacuum at velocity v cannot emit a single photon.
My ideas:
Momentum is conserved. Energy is conserved.
Hence (E(before)=E(after)): gamma(before)*m(e)*c^2 = E(photon) + gamma(after)*m(e)*c^2
where E(photon)=hc/lamda
(P(before)=P(after)): gamma(before)*m(e)*v(after) = E(photon)/c + gamma(after)*m(e)*v(after), where P and v are vectors.
This is where I get stuck. Do I have to worry about the emisssion angle - i.e. does the electron change direction? How do I proceed?
--
Also, where can I find information about two body decay of a moving particle?
I have computed the energy and velocity of a particle (pi meson), which now decays into two photons. I imagine the photon energies depend on the emission angles - but how?
1. Show that a free electron in a vacuum at velocity v cannot emit a single photon.
My ideas:
Momentum is conserved. Energy is conserved.
Hence (E(before)=E(after)): gamma(before)*m(e)*c^2 = E(photon) + gamma(after)*m(e)*c^2
where E(photon)=hc/lamda
(P(before)=P(after)): gamma(before)*m(e)*v(after) = E(photon)/c + gamma(after)*m(e)*v(after), where P and v are vectors.
This is where I get stuck. Do I have to worry about the emisssion angle - i.e. does the electron change direction? How do I proceed?
--
Also, where can I find information about two body decay of a moving particle?
I have computed the energy and velocity of a particle (pi meson), which now decays into two photons. I imagine the photon energies depend on the emission angles - but how?