Relativity - Lorentz Force Law

  • Thread starter deadringer
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Assuming the Lorentz force law and also that in the rest frame of the particle the 3 acceleration is zero, we need to explain why the following equations hold:

E.v = 0 and E + v.B = 0

where v is the velocity.

I think this is because g(A,A) = -a squared is invariant. Therefore if a=0, I think this means that A must equal zero in every frame. Is this true, or can A be non zero and we get g(A,A) = 0 (i.e A is null).
 

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  • #2
Meir Achuz
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I am not sure what you mean by A and a, but acceleration is not a 4-vector, and has complicated LT properties.
In the rest frame for a=0, E=0, and B is unknown.
Since E=0, E' in a system moving with velocity v is given by
[tex]{\vec E}=\gamma{\vec v}\times{\vec B}[/tex], so
[tex]{\vec v}\cdot{\vec E'}=0.[/tex]
 
  • #3
Meir Achuz
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[tex]E=|{\vec E'}|=\gamma v B[/tex],
but [tex]{\vec v}\cdot{\vec B'}=v B[/tex].

Therefore [tex]E'+{\vec v}\cdot{\vec B'}[/tex]
does not equal zero.
 
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