- #1

curiousburke

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In Morin, "Special Relativity For the Enthusiastic Beginner", he explains the loss of simultaneity and specifically the "rear clock ahead" effect. If clocks are synchronized in the "train" frame (L long, v velocity), the rear clock will be ahead by L*v/c^2 when it is simultaneous with the front clock as view from the ground frame.

What I'm wondering, and I have not worked through the math, is whether the time which the back clock is ahead fully explains length contraction as well in that the back of the train would move forward during the time L*v/c^2. Basically, is length contraction just another way of expressing simultaneity effects?